A Train After Travelling 150 Km Meets With An Accident . Let s = the normal speed of the train then Two trains 150 miles apart are travelling toward each other.
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Total distance which needs to be covered = (300+150)m = 450m. Had the accident occurred 360 km further, it would have reached the destination 4 hours late. Had the accident occurred 6 0 km later, the train would have reached 3 0 minutes earlier.
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A train after travelling 50 km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late. A train 300 m long is running at a speed of 54 km/hr. Had the accident occurred 360 km further, it would have reached the destination 4 hours late. Now you can use d = s * t = 30 * 60/60 = 30 km.
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Speed = {54 × (5/18)} m/sec = 15 m/sec. Had the accident occurred 360 km further, it would have reached the destination 4 hours late. Total distance which needs to be covered = (300+150)m = 450m. #revoclasses #shorttrickmaths #aptitudea train meets with an accident after travelling 30 kms, after which it moves with 4/5 th of its original speed and.
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Therefore distance between a and b $=100+150=250$ km. What is the total distance traveled by the train?: After travelling 3 hours a train meets with an accident due to this it stops for an hour. Had the accident occurred 30 kms further, the train would have been late by only 21 minutes. I.e., after travelling $100$ km, train takes $3$.
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The length of journey is If the accident would occur at 150 km ahead in the same line then the train reaches only 3.5 hours late. Thus unusual time which is require to complete the journey = 5 × 2 = 10 hours. Now you can use d = s * t = 30 * 60/60 = 30 km. Then.
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Required time = 450 / 15 = 30 seconds If the accident would occur at 150 km ahead in the same line then the train reaches only 3.5 hours late. Let us assume the distance the train has to cover after the accident as $ y $ km and the speed of the train before the accident is $ x.
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A train after traveling for 50km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late. (a) 960 km (b) 870 km (c) 840 km (d) 1100 km A train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives.
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In what time will it pass a bridge 150 m long? Total distance which needs to be covered = (300+150)m = 450m. After travelling for 3 0 minutes a train meets with an accident, due to which it has to stop for 4 5 minutes. Thus, extra time = 2 hour. The speed of the train is?
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Therefore distance between a and b $=100+150=250$ km. So the speed of the train after the accident is $ \dfrac{3}{4}x $ km/hr. After this the train moves at 75% speed of its original speed and reaches to destination 4 hours late. What is the total distance travelled by the train? In what time will it pass a bridge 150 m.
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The speed of the train is? A train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives at its destination 8 hours late. Let y be the balance distance to be covered and x be the former speed. So the speed of the train after the accident is $ \dfrac{3}{4}x.
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What is the total distance traveled by the train?: Thus, extra time = 2 hour. Two trains 150 miles apart are travelling toward each other. Had the accident occurred 360 km further, it would have reached the destination 4 hours late. Had the accident occurred 6 0 km later, the train would have reached 3 0 minutes earlier.
Source: www.cbs.com
A train meets with an accident and travels at 4/7th of its regular speed hereafter and hence it reaches its destination 36 minutes late. A train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives at its destination 8 hours late. #timeanddistancebyprabhakarsir #careeradhyapana train after travelling 225 km meets with.
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Had the accident occurred 30 kms further, the train would have been late by only 21 minutes. I.e., after travelling $100$ km, $\dfrac{1}{4}$ of the original time to cover remaining distance is $45$ minutes. Had the accident occurred 6 0 km later, the train would have reached 3 0 minutes earlier. Due to the accident its speed is also reduced.
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Total distance which needs to be covered = (300+150)m = 450m. Had the accident occurred 360 km further, it would have reached the destination 4 hours late. Thus, extra time = 2 hour. It means it covers 300 km distance in 5 hours. Speed = {54 × (5/18)} m/sec = 15 m/sec.
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The delay in arrival is the time difference between the time the train takes to cover the rest distance $ y $ after the accident and time it would have taken without the. Had the accident occurred 6 0 km later, the train would have reached 3 0 minutes earlier. What is the total distance travelled by the train? After.
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A train meets with an accident and travels at 4/7th of its regular speed hereafter and hence it reaches its destination 36 minutes late. A train after travelling 50 km meets with an accident and then proceeds at 3/4 of its former speed and arrives at its destination 35 minutes late. Had the accident occurred 6 0 km later, the.
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After travelling for 3 0 minutes a train meets with an accident, due to which it has to stop for 4 5 minutes. #timeanddistancebyprabhakarsir #careeradhyapana train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives. What is the total distance travelled by the train ? A train 300 m long.
Source: suomiweed.com
Therefore distance between a and b $=100+150=250$ km. I.e., after travelling $100$ km, $\dfrac{1}{4}$ of the original time to cover remaining distance is $45$ minutes. The delay in arrival is the time difference between the time the train takes to cover the rest distance $ y $ after the accident and time it would have taken without the. A) 36.
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#revoclasses #shorttrickmaths #aptitudea train meets with an accident after travelling 30 kms, after which it moves with 4/5 th of its original speed and a. Thus, extra time = 2 hour. Thus unusual time which is require to complete the journey = 5 × 2 = 10 hours. A train after travelling 150 km meets with an accident and then.
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A train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives at its destination 8 hours late. The length of journey is Thus, extra time = 2 hour. Now you can use d = s * t = 30 * 60/60 = 30 km. It means it covers 300 km.
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Due to the accident its speed is also reduced to 3 2 of its former value and the train reaches its destination 1 hour 3 0 minutes late. #timeanddistancebyprabhakarsir #careeradhyapana train after travelling 150 km meets with an accident and then proceeds at 3/5 of its former speed and arrives. Had the accident occurred 360 km further, it would have.
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Had the accident occurred 30 kms further, the train would have been late by only 21 minutes. The length of journey is A train meets with an accident and travels at 4/7th of its regular speed hereafter and hence it reaches its destination 36 minutes late. A train after travelling 150 km meets with an accident and then proceeds at.
